In a non-leap year, what is the probability that the last day of the year stars with a 't'? (a) 4/7 (b) 1 (c) 0 (d) 2/7
Answers
Answered by
16
ANSWER
Step-by-step explanation:
PER WEAK NO.OF DAYS=7
T START with TUESDAY AND THURSDAY=2
SO,2/7
ANSWER IS =2/7
Answered by
3
Answer:
The correct answer of this question is option D,2/7.
Step-by-step explanation:
We have to solve this problem by using probability theory.
And according to the probability theory we have to give the total number of days starting with letter T by the total number of days in a way to get the probability of being a day which starts with letter T.
Number of days starts with letter T= 2(Thursday and Tuesday)
Number of days in a week is 7.
So the probability will be 2/7.
That's why the correct answer of this question is option D.
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