In a normal distribution, 100 percent of population lies within ±3σ of the mean * a)True b) False
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Answer:
Given, mean of binomial distribution μ=np=25
We have ,Variance =σ2=npq
Now,
0≤p<1
and
0≤q≤1
⇒0≤npq≤np
⇒0≤σ2≤25
⇒−5≤σ≤5
But σ≥0
∴0≤σ<5
σ∈[0,5)
Step-by-step explanation:
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