Question

In a nuclear reactor, a very slow-moving neutron is absorbed by a stationary boron atom. The equation for the nuclear reaction is
1n + 10B → 7Li + 4He
0 5 3 2
After the reaction, the speed of the helium atom is 9.1 x 106 ms-1 and the kinetic energy of the neutron is approximately zero.
Given:
mn = 1.008665 u;
mB = 10.0130 u;
mLi = 7.0160 u;
mHe = 4.0026 u.
Calculate
a) the kinetic energy of the lithium atom after the reaction.
b) the reaction energy in MeV and Joule.

Answer 1

In a nuclear reactor, a very slow-moving neutron is absorbed by a stationary boron atom. The equation for the nuclear reaction is

1n + 10B → 7Li + 4He

0 5 3 2

After the reaction, the speed of the helium atom is 9.1 x 106 ms-1 and the kinetic energy of the neutron is approximately zero.

Given:

mn = 1.008665 u;

mB = 10.0130 u;

mLi = 7.0160 u;

mHe = 4.0026 u.

Calculate

a) the kinetic energy of the lithium atom after the reaction.

b) the reaction energy in MeV and Joule.

Answer 2

Answer:

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