Question

In a number of two digits, the digit at ten's place is 6 times the digit in unit place. If the digits are reversed the difference of the new number so formed and the original number is 45. Find the number ​

Answer 1

Answer:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i) 

Reversed number = 10y + x 

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4  x=3y  ∴x=6

y=2

∴ Number = 62

Answer 2

Answer:

x=30

y=6

number=30,6

explanation:

let the one's digit be y and ten's digit be x number =10x+y

then,x=6y...(i)

Reversed number=(10y+x)=45 put x =6y in eg.(i)

=> 9x -9y=45

=> x -y=5....(ii)

=>6y-y=5

so that, 5y=5x=6y

x= 30

y=6

find the number: 30,6