Question

In a pack of 52 cards, find the probability of (1) a perfect cube (ii) prime number card between 1 and 10.

Answer 1

Step-by-step explanation:

here perfect cubes are only 1 and 8 so the probability will be the= 2/13. and total no .of prime number card between 1 and10 is given by 4/13. hoped this may help you☺. please mark me as brainliest

Answer 2

(i)The probability of getting a perfect cube=$\frac{3}{52}$

(ii)Probability of getting  a prime number card between 1 and 10=$\frac{1}{13}$

Step-by-step explanation:

Total number of cards in a pack=52

(i).Perfect cube number in pack=1,8,27

Probability,P(E)=$\frac{Favorable\;cases}{Total\;number\;of\;cases}$

We have favorable cases=3

Total number of cases=52

Using the formula

The probability of getting a perfect cube=$\frac{3}{52}$

(ii) Prime number card between 1 and 10=2,3,5,7

Favorable cases=4

Probability of getting  a prime number card between 1 and 10=$\frac{4}{52}=\frac{1}{13}$

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