In a parallelogram ABCD,2 points Per and Q are taken on diagonal BD such that DP=BQ
Show that
1) Triangle APD is congruent to triangle CQB
2) AP is congruent to CQ
3) AQ is congruent to CP
4) APCQ is a parallelogram
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Answer:
1 DP=BQ (GIVEN)
AD=BC (ABCD IS A PARALLELOGRAM)
angle 1=angle 2 (ALTERNATIVE ANGLE)
Hence, ∆APD congruent to ∆CQB
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