in a parallelogram ABCD 4 angle A =5Angle B find angle C
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Step-by-step explanation:
In a parallelogram ABCD if ∠A is 54 of ∠B, then what is ∠A?
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ANSWER
Since from the property of parallelogram,
The sum of angle on the same side of the line AB is equal to
180o, i.e.
∠A+∠B=180o
∠A=54∠B (Given)
⇒54∠B+∠B=180o
=59∠B=180o
=∠B=9180×5=180o
=∠B=100o
⇒∠A=54∠B=54×100
∠A=80o
∠B=100o
Question;♡♡♡✧♥
Angle a and angle b are linear pair of angles. If 4angle a=5angle b then find angle a and angle b.
Given;༶•┈┈⛧┈♛♛•༶♥
- ≤A and ≤B are linear pair of angles.
- 4≤A = 5≤B
To find; .・゜゜・♥
Angle A(≤A) and Angle B(≤B).
Solution;♛⛧•༶♥
- 4≤A = 5≤B
- ≤A = 5≤B/4
So,▧▧♡♡♡
- ≤A + ≤B = 180°
5≤B/4 + ≤B = 180°
9≤B/4 = 180°
9≤B = 180×4
≤B = 720/9
≤B = 80°
Then,▥▥♡♡♡
≤A = 5≤B/4
≤A = (5×80)/4
≤A = 400/4
≤A = 100°
Now, ▤▤♡♡♡
- ≤A = 100°
- ≤B = 80°
- ≤C = ≤A = 100° [Internal vertically opposite angles]
- ≤B = ≤D = 80° [Internal vertically opposite angles]
We have found;░░░♥
≤C = 100°
Analysis;.・゜-: ✧ :-♥
Angle a and b are linear pairs... and Angle A and B has given.
Process used to solve;⋇⋆✦⋆⋇♥
- The Sum of linear pairs angle is 180°
≤A + ≤B = 180°
- ≤ is denoted as Angle.
Try to say;☆♬○♩●♪✧♩♥
I hope it will helpful for you.
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