Question

In a parallelogram ABCD A = 5x - 20 and C = 3x +10
find x in all the angles..............pls

Answer 1

for all that I understand in the question, I am writing an answer

as ABCD is a parallelogram, angle A =angle C
now.
$given \\ 5x - 20 = 3x + 10 \\ 5x - 3x = 10 + 20 \\ 2x = 30 \\ x = 15$
let's find the angles
$angle \: a = angle \: c = 3 \times 15 + 10 = 55 \: degrees \\ now \\ angle \: a + angle \: b = 180 \\ 55 + angle \: b = 180 \\ angle \: b = 125 \\ as \: angle \: b \: and \: angle \: d \: are \: opposite \: angles \: of \: a \: parellelogram \\ angle \: b = angle \: d = 125 \: degrees$
therefore,
angles of the parallelogram
angle A = 55 degrees
angle B = 125 degrees
angle C = 55 degrees
angle D = 125 degrees

Answer 2

A.T.Q

3X+10+5X-20 =180 (adjacent angles are supplementary)

8x-10 =180

8x = 180 -10
8x =170
x= 170/8
x=21 .25
A= 5×21.25 -20 =86.25 =D,C=3×21.25+10=73.75=B