Question

in a parallelogram abcd angel a = to angel b + 50 degree then find the measure of each angel​

Answer 1

Answer:

Answer: four angles of parallelogram that is quadrilateral ABCD are ∠A = 115° , ∠B = 65° , ∠C = 115° and ∠D = 65°. so Now we have ∠B = x = 65° and ∠A = x + 50 = 115°.

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Answer 2

Step-by-step explanation:

We know that sum of two adjacent angles of a parallelogram is 180°

∴ ∠A+∠B=180°

------ ( 1 )

It is given that ∠B is 50° more than ∠A.

∴ ∠B=∠A+50°

------ ( 2 )

Now, substituting ( 2 ) in ( 1 ),, we get

⇒ ∠A+∠B=180°

⇒ ∠A+∠A+50°=180°

⇒ 2∠A+50°=180°

⇒ 2∠A=180° −50°

⇒ 2∠A=130°

∴ ∠A=65°

⇒ ∠B=∠A+50°

=65° +50°=115°

In a parallelogram, the opposite angles are equal in magnitude.

∴ ∠A=∠C=65°

∴ ∠B=∠D=115°