in a parallelogram ABCD,angle d =115 ,determine the measure of angle a and angle b
Answers
Answered by
72
Given:-
ABCD⇒║gm
D=115°
To find:-A°and B°
Solution:-
∠D=115°
∠C=180°-∠D(Co-interior angles are supplementary)
∠C=180°-115°
∠C=65°
∴∠A=65°(Opposite angles in a ║gm are equal)
∠B=115°(Opposite angles in a ║gm are equal)
Answered by
15
Answer:
Step-by-step explanation:
We need to analyze the properties of a parallelogram.
The properties are as follows:
Given parallelogram ABCD then:
1) Sides AB and CD are parallel and equal whereas side Ad and DC are parallel and equal.
2) ∠a = ∠ b that is opposite angles are equal.
3) Adjacent angles that is ∠a and ∠d are supplementary.
From the given properties we can now answer the question.
∠d and ∠b are opposite hence they are equal.
∠d is adjacent to ∠a hence they are supplementary.
∠b = 115°
∠a = 180 - 115 = 65°
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