In a parallelogram ABCD angleA=(2X+10)°and Angle c= (3x-20)° . find the value of x
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Answered by
24
Given - ABCD is a parallelogram
A=2X+10
C=3X-20
To find- X
Solution- A =C ( opposite angles of parallelogram are equal)
2X+10=3X - 20
2X-3X=-20-10
-X=-30
X=-(-30)
X=30°
Answered by
13
Heya !
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ANSWER :-
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Since , opposite angles in a Paralellogram are equal , given that /_A and /_C .
So ,
(2x + 10)° = (3x - 20)°
=> 2x + 10 = 3x - 20
=> 2x - 3x = - 10 - 20
=> - x = -30
( Both side minus gets cancelled so x = 30 )
Therefore ,
= x = 30
Ans : The value of 'x' is 30 .
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HOPE HELPS !
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# Brishti ^_^
—————————
ANSWER :-
—————————
Since , opposite angles in a Paralellogram are equal , given that /_A and /_C .
So ,
(2x + 10)° = (3x - 20)°
=> 2x + 10 = 3x - 20
=> 2x - 3x = - 10 - 20
=> - x = -30
( Both side minus gets cancelled so x = 30 )
Therefore ,
= x = 30
Ans : The value of 'x' is 30 .
—————————
HOPE HELPS !
—————————
# Brishti ^_^
LovelyBarshu:
Tabbhi same cuz they r opposite angles only if value remains same !
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