Math, asked by ananyakn0924, 10 months ago


In a parallelogram ABCD, bisectors of angles A and B intersect each other at E which lies on DC, then find angle AED.​

Answers

Answered by venkatesh175058
1

the angle created by a AED is 90 degree

Answered by DevendraLal
2

In a parallelogram ABCD, bisectors of angles A and B intersect each other at E which lies on DC, then find angle AEB.​ (This is the correct question)

Given:

Bisectors of angles A and B intersect each other at E which lies on DC.

To find:

angle AEB

Solution:

1) In the parallelogram y the angle sum property of the parallelogram we have,

  • 2x + 2x +2y +2y = 360°
  • 4x + 4y = 360°
  • x + y = 90°

2)In ΔAEB ( by the angle sum property of the triangle)

  • x+ y +∠AEB = 180°
  • ∠AEB = 180-(x+y)
  • ∠AEB = 180 - 90
  • ∠AEB = 90°

The measurement of the required angle is 90°

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