In a parallelogram ABCD, bisectors of angles A and B intersect each other at E which lies on DC, then find angle AED.
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the angle created by a AED is 90 degree
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In a parallelogram ABCD, bisectors of angles A and B intersect each other at E which lies on DC, then find angle AEB. (This is the correct question)
Given:
Bisectors of angles A and B intersect each other at E which lies on DC.
To find:
angle AEB
Solution:
1) In the parallelogram y the angle sum property of the parallelogram we have,
- 2x + 2x +2y +2y = 360°
- 4x + 4y = 360°
- x + y = 90°
2)In ΔAEB ( by the angle sum property of the triangle)
- x+ y +∠AEB = 180°
- ∠AEB = 180-(x+y)
- ∠AEB = 180 - 90
- ∠AEB = 90°
The measurement of the required angle is 90°
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