Question

In a parallelogram ABCD E and F are the mid-point of BC and AD. Show that
(i) AFCE is a parallelogram

(ii) ∆ABE is congruent with ∆ CDF ​

Answer 1

Step-by-step explanation:

In the fig

AB=AE

then, AB is parallel to AE 1

In the fig

if, DC=FC

then DC us parallel to FC 2

from eqn 1 in 2

We get AFCE is a parallelogram

So we can also prove that ∆ABE is congruent to ∆CDF

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