in a parallelogram ABCD E,F are mid-piont of the side AB CD respectively
prove that:
1) triangles HEB and FHC are congruent
2)GEHF is a parallelogram
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Answer:
if ∆HEB congruent to ∆FHC
Hence by (C.P.C.T) AB=CD,AD=BC
Therefore, Opposite side of are equal and parllel
if one pair of opposite side are equal and pallel
hence, it is parllalogram
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