in a parallelogram ABCD if (2x+35)degree and angle (3x-5)degree.Find:the value of x (ii)measure of each angle of ABCD.
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In a parallelogram ABCD
(2x+35)+(3x-5)=180 (adjacent angles are supplementary
5x+30=180
5x=180-30
5x=150
x=150/5
x=30
(2x+35)=(2 (30)+35)=(60+35)=95
(3x-5)=(3 (30)-5)=(90-5)=85
so the angles are 95,85,95,85 (as opposite angles are equal in a parallelogram)
(2x+35)+(3x-5)=180 (adjacent angles are supplementary
5x+30=180
5x=180-30
5x=150
x=150/5
x=30
(2x+35)=(2 (30)+35)=(60+35)=95
(3x-5)=(3 (30)-5)=(90-5)=85
so the angles are 95,85,95,85 (as opposite angles are equal in a parallelogram)
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