Question

In a parallelogram ABCD ,if ∠A=( 3x-20)°, ∠B= (y+15)°, ∠C= (x+40)°, then find the measures of angles of parallelogram.

Answer 1

Answer:

hope it will you

thnku.......

Answer 2

Answer:-

Given:

In a parallelogram ABCD,

∠A = (3x - 20)°

∠B = (y + 15)°

∠C = (x + 40)°

We know that,

Opposite angles of a parallelogram are equal.

That is,

∠A = ∠C and ∠B = ∠D

Let ∠D = z°

Hence,

→ 3x - 20 = x + 40 and y + 15 = z

→ 3x - x = 40 + 20

→ 2x = 60

→ x = 60/2

→ x = 30

Now we have measures of two angles,

→ ∠A = 3 * 30 - 20 = 90 - 20 = 70°

→ ∠C = 30 + 40 = 70°

We know,

Sum of two adjacent angles of a parallelogram = 180°.

Hence,

∠A + ∠B = 180°

→ 70° + y + 15° = 180°

→ y = 180° - 15° - 70°

→ y = 95°

And,

∠C + ∠D = 180°

→ 70° + z = 180°

→ z = 180° - 70°

→ z = 110°

Therefore,

→ ∠B = 95 + 15 = 110°

→ ∠D = z = 110°

Therefore, the four angles of the given parallelogram are 70° , 110° , 70° , 110°.