In a parallelogram ABCD, if AB = y + 1, CD = 2x + 5, AD = y + 5 and BC = 3x – 4 then find the ratio of AB : BC .
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the ratio of AB: BC is 31:35
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☄️ Question :-
In a parallelogram ABCD, of AB = y+1, CD = 2x+5, and AD = y+5, BC = 3x-4, then find the ratio of AB : BC.
☄️ Solution :-
⭐ Given that ABCD is an parallelogram with sides :-
- AB = y+1
- CD = 2x+5
- AD = y+5
- BC = 3x-4
⭐ We have to find the ratio of AB : BC.
We know that in a parallelogram opposite sides are equal, so :-
- AB = CD
- AD = BC
⭐ Equating them :-
- y+1 = 2x+5
- y+5 = 3x-4
⭐ On solving them by substitution method, we get :-
- x = 13
- y = 30
Putting the values in AB, BC :-
- AB = y+1 = 30+1 = 31
- BC = 3x-4 = 3(13)-4 = 35
⭐ The ratio required = AB : BC = 31 : 35.
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