Question

In a parallelogram, ABCD, if AD= 10 cm ,CF = 8 cm , BG = 12 cm , find AB

Answer 1

area parallelogram =ad×bg
=120
area of parallelogram=ab×cf
120=ab × 8
ab=120/8
ab=15

Answer 2

Answer:

$AB = 15\:cm$

Step-by-step explanation:

$Given\\In \: ABCD \: parallelogram \\AD = 10\:cm ,\:BG = 12\:cm \\CF=10\:cm,\:AB=?$

$\boxed {Area\:of \: a \: parallelogram \\= base \times corresponding\: height}$

$Here, \\Area \: of \: parallelogram \:ABCD = AD \times BG --(1)$

$Area \: of \: parallelogram \:ABCD = AB \times CF --(2)$

/* Form \: (1)& (2) , we \: know \: that,\\(1)=(2) */

$10\:cm \times 12\:cm = AB \times 8\:cm$

$\implies \frac{120}{8}=AB$

$\implies 15 \:cm = AB$

Therefore,

$AB = 15\:cm$

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