in a parallelogram abcd if ad 10cm cf 8cm bg 12cm.find the ab.
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area of parallelogram = base x height = ad x cf = 80 cm ^2.
when height is taken as bg, the base is ab.
area of parallelogram = base x height = ab x bg
=> base AB = 80 / 12 = 6.67cm.(ANS)
when height is taken as bg, the base is ab.
area of parallelogram = base x height = ab x bg
=> base AB = 80 / 12 = 6.67cm.(ANS)
this is the right answer
wrong
no its right
whose are u saying wrong mine or his
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Given
ABCD is a parallelogram and AD = 10 cm, CF = 8 cm, BG = 12 cm
Area of parallelogram ABCD = AB ´ CF = AB ´ 8 → (1)
Also area of parallelogram ABCD = AD ´ BG = 10 ´ 12 = 120 sq cm → (2)Equations
(1) and (2) represent the same,Hence AB ´ 8 = 120
Therefore AB = 15 cm
ABCD is a parallelogram and AD = 10 cm, CF = 8 cm, BG = 12 cm
Area of parallelogram ABCD = AB ´ CF = AB ´ 8 → (1)
Also area of parallelogram ABCD = AD ´ BG = 10 ´ 12 = 120 sq cm → (2)Equations
(1) and (2) represent the same,Hence AB ´ 8 = 120
Therefore AB = 15 cm
Similar questions
Area of parallelogram ABCD = AB ´ CF
= AB ´ 8 → (1)
Also area of parallelogram ABCD = AD ´ BG
= 10 ´ 12 = 120 sq cm → (2)
Equations (1) and (2) represent the same,
Hence AB ´ 8 = 120
∴ AB = 15 cm