In a parallelogram ABCD, if <A=(3x+12)°,<B=(2x-32 then find the value of x and then find the measures of <C and <D
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Answer:
hi mate
Step-by-step explanation:
angle A + angle B =180°
because sum of adjacent angles in a parallelogram is 180°
3x+12+2x-32=180
5x=180-12+32
5x=200
x=40
therefore angle A =3×40+12=132°
and angle B=2×40-32=48°.
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