Math, asked by simranpatil2005, 11 months ago

In a parallelogram ABCD, if <A=(3x+12)°,<B=(2x-32 then find the value of x and then find the measures of <C and <D​

Answers

Answered by Anonymous
9

Answer:

hi mate

Step-by-step explanation:

angle A + angle B =180°

because sum of adjacent angles in a parallelogram is 180°

3x+12+2x-32=180

5x=180-12+32

5x=200

x=40

therefore angle A =3×40+12=132°

and angle B=2×40-32=48°.

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