In a parallelogram ABCD K is the mid point
of side CD and DM is drawn Parallel to BK,
which meets CB Produced at M and cut side
AB at L. Prove that ADF = 1/2 CM.
Answers
If K is the mid point of side CD and DM is drawn parallel to BK, which meets CB produced at M and cut side AB at L then AD = 1/2 CM is proved below.
Step-by-step explanation:
Referring to the figure attached below the question is solved as follows:
Step 1:
In ∆ DCM, we are given
K is a midpoint of side CD and DM // BK
Since we know that, in a triangle, the line-segment joining the midpoints of any two sides will be parallel to the third side and half its length, therefore we can conclude that
B is also the midpoint of side CM
And,
CB = BM = ½ CM …… (i)
Step 2:
ABCD is given to be a parallelogram.
And we know that the opposite facing sides of a parallelogram are equal in length, therefore, we get
AD = CB ……. (ii)
Now, from (i) & (ii), we get
AD = ½ CM
Hence proved
Hope this is helpful!!!!!
Step-by-step explanation:
Muwhich meets CB Produced at M and cut side ... K is the mid point of side CD and DM is drawn parallel to BK, ... M and cut side AB at L then AD = 1/2 CM is proved below .
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