in a parallelogram ABCD <A=(2x+10)°,<C=(3x-20)°find the value of x
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Answered by
2
as we know that <a=<c.
so 2x+10=3x-20
10+20=3x-2x
x=30
so 2x+10=3x-20
10+20=3x-2x
x=30
Answered by
7
given that in aparallelogram
angle a = 2x +10
angle b = 3x-20
we know that the opposite angles of a parallelogram are equal
<a = <c
as per question
2x+10 = 3x-20
2x - 3x = -20 -10
-1x = -30
x = 30/1
the value of x = 30
pls mark it as brainliest
angle a = 2x +10
angle b = 3x-20
we know that the opposite angles of a parallelogram are equal
<a = <c
as per question
2x+10 = 3x-20
2x - 3x = -20 -10
-1x = -30
x = 30/1
the value of x = 30
pls mark it as brainliest
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