Math, asked by virajambhore, 3 months ago

. In a parallelogram ABCD, m∠A=x° and m∠B=(3x+20)°, find m∠C and m∠D.​

Answers

Answered by nsnsnsnsneennsnsn
1

Answer:

b b b j j h j ch gk fuzgoczriif fi gk

Answered by Ijazulhassan
1

Answer:

In parallelogram ABCD,

Angle A + Angle B = 180°

(Adjacent angles of parallelogram)

x + 3x + 20° = 180°

4x = 180° - 20°

x = 160°/4

x = 40°

Now,

Angle A = x = 40°

Angle B = 3x +20° = 120°+20° = 140°

Angle A = Angle C = 40°

Angle B = Angle D = 140°

(Opposite angles in a parallelogram)

Similar questions