. In a parallelogram ABCD, m∠A=x° and m∠B=(3x+20)°, find m∠C and m∠D.
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Answered by
1
Answer:
In parallelogram ABCD,
Angle A + Angle B = 180°
(Adjacent angles of parallelogram)
x + 3x + 20° = 180°
4x = 180° - 20°
x = 160°/4
x = 40°
Now,
Angle A = x = 40°
Angle B = 3x +20° = 120°+20° = 140°
Angle A = Angle C = 40°
Angle B = Angle D = 140°
(Opposite angles in a parallelogram)
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