In a parallelogram ABCD points P and Q are points of trisection of diagonal BD. Prove that CQ is parallel to AP
Answers
Answered by
36
hello ☺
Given:
AC and BD are the diagonals of the parallelogram ABCD which intersect O. The points P and Q trisects the diagonal BD.
To prove:
(i) CQ || AP
(ii) AC bisect PQ.
Proof:
AC and BD bisect each other at O.
OB = OD
OA = OC
P and PQ trisects the diagonal BD.
∴ DQ = PQ = BP
OB = OD
BP = DQ
∴ OB – BP = OD – DQ
⇒OP = OQ
so in Quadrilateral APCQ diagonals AC and PQ are such that OP = OQ and OA = OC
the diagonals AC and PQ bisect each other at O.
Hence, APCQ is a parallelogram.
∴ CQ || AP
Thank you
Given:
AC and BD are the diagonals of the parallelogram ABCD which intersect O. The points P and Q trisects the diagonal BD.
To prove:
(i) CQ || AP
(ii) AC bisect PQ.
Proof:
AC and BD bisect each other at O.
OB = OD
OA = OC
P and PQ trisects the diagonal BD.
∴ DQ = PQ = BP
OB = OD
BP = DQ
∴ OB – BP = OD – DQ
⇒OP = OQ
so in Quadrilateral APCQ diagonals AC and PQ are such that OP = OQ and OA = OC
the diagonals AC and PQ bisect each other at O.
Hence, APCQ is a parallelogram.
∴ CQ || AP
Thank you
Attachments:
Similar questions