in a parallelogram ABCD side AB =diagonal BD then prove that AC^2=BD^2+BC^2
Answers
Answered by
14
Step-by-step explanation:
ANSWER
ABCD is a parallelogram so, AB∣∣CD and AD∣∣BC
AC
=
AB
+
BC
(addition Theorem)
BD
=
BA
+
AD
(addition Theorem)
AC
+
BD
=
AB
+
BC
+
BA
+
AD
=
AB
+
BC
−
AB
+
BC
=2
BC
Answered by
9
Step-by-step explanation:
Mark mah sweet Unnie as brainlist.. okh
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