Question

In a parallelogram ABCD , The bisector of angle A and B meet at O .Then proof angle O 90 degree​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

ABCD is a parallelogram

⇒ ∠A+∠B=180

o

[ Sum of adjacent angles of parallelogram are supplementary ]

⇒

2

1

∠A+

2

1

∠B=

2

180

o

⇒ ∠OAB+∠OBA=90

o

In △AOB

⇒ ∠OAB+∠AOB+∠OBA=180

o

⇒ ∠AOB=180

o

−(∠OAB+∠OBA)

⇒ ∠AOB=180

o

−(∠OAB+∠OBA)

⇒ ∠AOB=180

o

−90

o

∴ ∠AOB=90

o