Math, asked by shaikhtalib37, 5 months ago

In A parallelogram ABCD,the measure of angle A js twice the measure of angleB.find measure AngleA And B​

Answers

Answered by AyushKunal
0

Step-by-step explanation:

Let angle B be x.

Angle A=2x

Angle C=Angle A=2x

Angle D=Angle B=x

According to the question,

x+2x+x+2x=180°

6x=180°

x=180°/6

x=30°

Angle B=x

=30°

Angle A=2x

=2*30°

=60°

Hope, it will be helpful!

Answered by wkchathura1974
0

Answer:

B = Angle opposite to B ( in a parallelogram, angles opposite to each other are equal in magnitude)

A = angle opposite to A

∴B+B+A+A+= 360° (sum of interior angles of a quadrilateral is 360°)

A= 2B

∴ B+B + 2B+ 2B = 360°

⇒6B = 360°

⇒B = 360°/6 = 60°

A = 2B =2×60° = 120°

∴A=120° & B = 60°

Step-by-step explanation:

Hope it's clear

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