In a parallelogram ABCD, the measure of angleA exceeds thrice the measure of angleB by 20degree. Find the measures of angle A and angelB.
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Let B=X ,A=3X+20
In parallelogram ABCD
A+B=180(Sum of adjacent angles)
x+3x+20=180
4x=180-20
4x=160
x=160/4=40
A=140° and B=40°
In parallelogram ABCD
A+B=180(Sum of adjacent angles)
x+3x+20=180
4x=180-20
4x=160
x=160/4=40
A=140° and B=40°
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