Question

In a parallelogram opposite anglemeasures (60-x)° and (3x-4)°,then find the measures of angles of the parallelogen​

Answer 1

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We know that sum of all angles of a parallelogram us equal;so,

60-x=3x-4

-x-3x= -4-60

-4x= -64

$\sf \: x = \cancel\frac{ \cancel- 64}{ \cancel - 4} = 16$

Angles are:

69-x=60-16=44°

3x-4=3×16-4= 48-4=44°

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Answer 2

answer:

32 and 80

Step-by-step explanation:

the procedure is that opposite angles of a parallelogram are equal.