in a parallelogram pqrs the bisector of P and Q meet at O find the angle pqr
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Answer:
Given
∠SPO=∠POQ
∠OQR=∠POQ
∵∠P+∠Q=180° [∵PS║QR]
∠SPO+∠OQR=\frac{180}{2}
∠SPO+∠OQR=90°
∠O=180°-90° (By Angle Sum Property)
∠O=90°
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Answer:
answer, √90°............
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