Question

The angular velocity of a wheel increase from 1200 to 4500 rev/min in 10 sec. The number of revolution made during this time

Answer 1

initial angular velocity, w1 = 1200 rpm = 1200*2pi/60 = 40 pi rad/s  

Final angular velocity, w2 = 3120 rpm = 3120*2pi / 60 = 104 pi rad/s  

Time t = 16 s  

(i)Angular acceleration, a = (104-40)/16 = 64pi/16 = 4 pi rad/s^2  

(ii) Angle, theta = 40pi*16 + ½*4pi * 256 = 1152pi rad  

Thus, number of revolutions, n= 1152pi/2pi revolutions  

= 576 rev

Answer 2

576 revolutions

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