Question

In a Pentagon ABCDE.AB is parallel to ED. If B is 140 find angles E and D if E:D=5:6

Answer 1

Hi dear

Since AB||ED and AE is the transversal∠A + ∠E = 180° [Sum of interior angles on the same side of transversal] Given ∠B = 142°, ∠C = 3x and ∠D = 2x We know that sum of angles in a pentagon = 540°Hence ∠A + ∠B + ∠C + ∠D + ∠E = 540°180°  + 142° + 3x + 2x = 540° 322° + 5x = 540° 5x = 540 – 322 = 218 Therefore x = 218/5  

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