In a photo electric expriment the photon of energy 5ev are incident on a metal surface. the liberate electrons wgich are just stipped by an electrode at a potential of-3.5v with respect to the meteo. the work function of the metal in ev
Answers
If the liberated electrons which are just stipped by an electrode at a potential of-3.5v with respect to the metal, then the work function of the metal in eV is 1.5 eV.
Explanation:
The energy of the photon, E = 5 eV
The potential at the electrode, Vo = - 3.5 V
Let the work function of the metal be denoted as “∅”.
We know that in the photoelectric the photon energy incident on the surface of the metal is equal to the sum of the work function of the metal and the maximum kinetic energy of the electron.
Therefore,
E = K.E.max(electron) + ∅
⇒ E = [e |Vo|] + ∅
⇒ ∅ = E – [e |Vo|]
since 1 eV is the kinetic energy acquired by an electron or a proton acted upon by a potential difference of 1 volt, ∴ for 3.5 V the K.E will be = 3.5 eV
⇒ ∅ = 5 – |-3.5|
⇒ ∅ = 5 – 3.5
⇒ ∅ = 1.5 eV
Thus, the work function of the metal in eV is 1.5 eV.
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