Question

In a photoelectric effect experiment, for radiation with
frequency υ₀ with hυ₀ = 8eV, electrons are emitted with
energy 2 eV. What is the energy of the electrons emitted for
incoming radiation of frequency 1.25 υ₀ ?
(a) 1 eV (b) 3.25 eV
(c) 4 eV (d) 9.25 eV.

Answer 1

Answer:

(c) 4 eV IS THE CORRECT ANSWER

Explanation:

Photoelectric Effect

KE  

max

​  

=hv  

o

​  

−W  

o

​  

 

2ev=8eV−W  

o

​  

 

W  

o

​  

=6eV

Now for frequency 1.25v  

o

​  

 

KE  

max

​  

=1.25hv  

o

​  

−W  

o

​  

 

KE  

max

​  

=1.25(8)−6eV=4eV

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