Question

In a polynomial p(x)=x²+x+41 put different values of x and find p (x). Can you conclude after putting different values of x that p (x) is prime for all. Is x an element of N? Put x = 41 in p (x). Now what do you find?

Answer 1

Answer:

P(41) is not prime

Step-by-step explanation:

P(x) = x²+x+41  

x P(x)  

0 41       Prime

1 43       Prime

2 47       Prime

3 53       Prime

4 61       Prime

5 71       Prime

6 83       Prime

7 97       Prime

8 113       Prime

9 131       Prime

10 151       Prime

41 1763      not  Prime

for x = 41

P(41)  = 41² + 41 + 41 = 41(41 + 1 + 1) = 41 * 43

hence P(41) is not prime