The organ A of a person has been damaged completely due to a poisonous waste material B has started accumulation in his blood, making it dirty. In order to save this person’s life, the blood from an artery in the person’s arm is made to flow into long tubes made of substance E which are kept in coiled form in a tank containing solution F. This solution contains three materials G,H and similar proportions to those in normal blood. As the person’s blood passes through long tubes of substance E, most if the wastes present in it go into solution. The clean blood is then put back into a vein in the person for circulation.
(a) What is organ A?
(b) Name the wastes substance B.
(c) What are (i) E, and (ii) F?
(d) What are G, H and I?
(e) What is the process described above known as?
Answers
c and e answers is above
a. A is kidney
b.urea
d.G water, H,Glucose, I salt
Answer:
a) From the above given question, we can understand that kidney is organ A. Kidney filters out blood and remove toxins and waste material . So damage to it will accumulate waste material in the blood.
b) Urea is the toxic waste material B found to be accumulated in blood due to kidney damage.
c) i) In order to save that person, dialysis is done in which arterial blood is made to flow into the dialyser where substance E called cellulose makes up the coiled cellophane tube.
ii) The dialysing solution is being represented as F.
d) Three materials which the dialysing solution contains are - water , salts and glucose which are being represented as G, H and I respectively.
e) This process of removal of waste and toxic material from blood using a machine is called dialysis.