Question

In a population of 2000 individuals,500 belong to the genotype AA. What would be the frequency of heterozygotes in this population? (Explain properly plzz)​

Answer 1

Answer:

Explanation:

given dominant individuals=500

so frequency PP=0.25(500/2000)

SO      P=0.5

NOW P+Q=1

THUS Q=0.5

as asked heterozygotes so 2pq=2*0.5*0.5

                                                      =0.5

Answer 2

The frequency of the heterozygotes will be 0.5 in the population of 2000 people

Explanation:

For calculating the frequency of heterozygotes we will use the formula

$p^2+2pq+q^2 = 1$

Where,

• p = frequency of dominant allele
• q = frequency of recessive allele

It is given that 500 individuals have AA genotype in 2000 population.

So,

Frequency of AA = $\frac{500}{2000}$ = 0.25

It means, $p^2 = 0.25$

So, p = 0.5

We know that in a population p + q = 1

So, q = 1 - p = 1 - 0.5 = 0.5

Now according to the above mentioned formula, the frequency of heterozygotes = 2pq

Frequency of heterozygotes = $2\times 0.5\times 0.5 =$ 0.5