In a population of 2000 individuals 900 individuals are suffering from a recessive autosomal disease and 500 are carriers the gene frequency of recessive gene is answer is 0.67 plz explain how
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It is because of the Hardy-Weinberg equation.
P^(2) + 2Pq + q^(2) = 1
Where P^(2) = Homozygous Dominant genotype OR normal
q^(2) = Homozygous Recessive genotype OR Diseased
Pq = Heterozygous Dominant phenotype OR Carrier
The question has provided us with total 2000 individuals with 900 diseased and 500 carriers. But for ease of calculation, let us divide everything by 20.
That gives us P^(2) + 25 + 45 = 100.
That leaves us with q^(2) = 45.
√45 = Nearly 6.7 .
In percentages, that will be about 0.67.
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