Question

In a population of plants, the allele for long stems (s) is completely dominant over the allele for short stems (s). if 35% of the population has short stems, calculate the percentage of the population that is expected to be heterozygous (ss). 48 percent 59 percent 41 percent 17 percent

Answer 1

Hey.

48% is the answer.

Refer to image attached.

HOPE THIS HELPS YOU.

Answer 2

Answer: The correct answer is- 48 percent.

As per the information, long stem ( depicyed by domiant allele 'S') is a dominant trait over short stem ( depicted by recessive allele 's')

Percent of population with short stem = 35% = 0.35

According to Hardy Weinberg law-

p² + q²+ 2pq = 1

where p² is frequency of homozygous dominant population, q² is homozygous recessive population, and 2pq is heterozygous dominant population.

Also, sum total of dominant and recessive allele frequency is 1 that is-

p+q = 1 ( p is frequency of dominant allele and q is frequency of recessive allele).

35% is the frequency of homozygous recessive population ( ss) that is

q² = 0.35

q= √0.35 = 0.59

p = 1- 0.59 = 0.41

Thus, population that is expected to be heterozygous -

2pq = 2× 0.59× 0.41

        = 0.48 = 48%