In a population with equilibrium condition 3360 individuals out of 4000 are tongue roller then what will be the number of individuals with heterozygous condition
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So basically this is a mendelian character where this is shown by homozygous dominant and heterozygous conditions. According to the hardy weinberg equation, 640 people can roll tongue now is q^2. Calculate the Q by given below
Total Population is 3600
Tongue rollers are 4000
Net non Tongue rollers -> 640
Fraction of Q² is 640/4000 =0.16
Therefore Q=0.4
from the question of hardy weinberg is -1
P+Q= 1
P=0.6
Now 2PQ shows heterozygous condition
=2*0.4*0.6*4000
=1920
640-> Non Tongue rollers
1920 -> PQ
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