Question

Show that BCD is a isocelies triangle

Answer 1

If bc=CD.. It's isosceles.. Where's the figure by the way

Answer 2

$\bf\huge{SOLUTION:-}$

let us assume a ∆BCD

which has sides BC,CD,BD

$\bf\huge{NOTE:-}$

Generally in an isosceles triangle there will be any 2 sides equal and 2 angles will be equal.

$\bf\huge{PROOF:-}$

Here in ∆BCD

(¡)<c = <D [< represents angle]

(¡¡)BD=BC [angles opposite to equal sides are considered as equal angles]

"Therefore, we proved that ∆BCD is a isosceles triangle"

$\bf\huge{EXAMPLE:-}$

(¡)BC=BD=6CM
(¡¡)<BCD=<BDC=65°

HERE, 2 ANGLES AND 2 SIDES ARE EQUAL AS PER OUR RULE OF ISOSCELES TRIANGLE.