Question

In a population with two alleles for a particular locus, B and b, the allele
frequency of B is 0.7. What would be the frequency of heterozygote if
the population is in Hardy-Weinberg equilibrium?
(a) 0.7 0.42 (c) 0.49 (d) 0.09 (e) 0.21​

Answer 1

Answer:

0.42

Explanation:

Frequency of allele P = 0.7 or 70%, Frequency of allele p = 0.3 or 30%.

From Hardy-Weinberg equilibrium : (p^2 + 2pq + q^2)

2pq (Heterozygous genotype) = 2 x 0.7 x 0.3 = 0.42 or 42%