Question

In A PQR, right-angled at Q, PR+QR = 25 cm and PQ = 5 cmn. Determine the values of
sin P, cos P and tan P.
Class 10 Maths exercise 8.1 question no 10
plz.answer fast​

Answer 1

Answer:

pls check question

reason is

Answer 2

Answer:

Step-by-step explanation:

PR + QR = 25   --------------(1)

By Pythagoras theorem

PR² = QR² + PQ²

PR²-QR²=5²

(PR+QR)(PR-QR) = 25

25(PR-QR) = 25  ( from (1))

PR-QR=1  ---------------------(2)

(1) + (2)

2PR = 26

PR =13

Substitute PR = 13 in (1)

13-QR = 1

QR = 12

PQ= 5

sin P = QR/PR = 12/13

cos P = PQ/PR = 5/13

tan P = QR/PQ = 12/5