Question

.In a ∆PQR right-angled at R, and PQ = 25 cm, PR= 24 cm Find QR?

Answer 1

Answer:

According to Pythagoras theorem,

(PR)² + (QR)² = (PQ)²

(QR)² = (PQ)² - (PR)²

(QR)² = (25)² - (24)²

(QR)² = 625 - 576

(QR)² = 49

QR = 7 cm