.In a ∆PQR right-angled at R, and PQ = 25 cm, PR= 24 cm Find QR?
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Answer:
According to Pythagoras theorem,
(PR)² + (QR)² = (PQ)²
(QR)² = (PQ)² - (PR)²
(QR)² = (25)² - (24)²
(QR)² = 625 - 576
(QR)² = 49
QR = 7 cm
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