In a ∆PQR ,the bisectors of PQR and PRQ meet at A . The perpendicular bisectors
of AQ and AR meet QR at B and C respectively. Show that the length of QR is equal to the
perimeter of ABC
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Answer:
130°
Step-by-step explanation:
QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°.
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