Question

in a quadratic equation if a=2,b=-6 and c=4 then find the value
$\alpha + \beta$
​

Answer 1

Given :-

• Coefficient of x² ( a ) = 2
• Coefficient of x ( b ) = - 6
• Constant term ( c ) = 4

To find :-

• α + β

Solution :-

As we know that

Sum of roots (α + β) = - b/a

Substituting the known values we have

→ - ( - 6 )/2

→ 6/2

→ α + β = 3

Hence , α + β = 3.

More information :-

• Sum of roots (α + β) = - b/a

• Product of roots (αβ) = c/a

Where

• a → coefficient of x²
• b → coefficient of x
• c → constant term

Quadratic polynomial :- x² - (α + β)x + αβ

Quadratic formula :- x = - b ±√b² - 4ac/2a

Methods of finding root of quadratic equations

• By using quadratic formula
• By completing the square
• By using PQ formula
• By factorisation .

Answer 2

Answer:

✡ Question ✡

➡ In a quadratic equation if a=2,b=-6 and c=4 then find the value $\alpha + \beta$

✡ Given ✡

⚫ Co-efficient of a = 2

⚫ Co-efficient of b = 6

⚫ Co-efficient of c = 4

✡ To Find ✡

➡ $\alpha + \beta$

✡ Formula Used ✡

➡ ( $\alpha + \beta$ ) = $\dfrac{-b}{a}$

✡ Solution ✡

By putting the value of α and β we get,

=> -$\dfrac{-6}{2}$

=> $\dfrac{6}{2}$

=> 3

Hence, the value of $\alpha + \beta$ = 3

Step-by-step explanation:

HOPE IT HELP YOU