In a quadrilateral ABCD, ∠A +∠C=140, ∠A:∠C=1:3 and ∠B:∠D=5:6, find angles A, B, C and D.
Answers
Given:
In a quadrilateral ABCD,
∠A +∠C = 140,
∠A : ∠C = 1 : 3
and
∠B : ∠D = 5 : 6
To find:
The angles A, B, C & D
Solution:
∵ Since ∠A : ∠C = 1 : 3, so let's assume,
"x" → represents the measure of the ∠A
"3x" → represents the measure of the ∠C
But, ∠A + ∠C = 140° (given)
∴ x + 3x = 140°
⇒ 4x = 140°
⇒ x =
⇒ x = 35°
∴ ∠A = x = 35°
and
∴ ∠C = 3x = 3 × 35° = 105°
We know, in quadrilateral ABCD, we have
∠A + ∠B + ∠C + ∠D = 360° ..... [angle sum property of a quadrilateral]
⇒ ∠B + ∠D + 140° = 360°
⇒ ∠B + ∠D = 360° - 140°
⇒ ∠B + ∠D = 360° - 140°
⇒ ∠B + ∠D = 220°
∵ Since ∠B : ∠D = 5 : 6, so let's assume,
"5y" → represents the measure of the ∠B
"6y" → represents the measure of the ∠D
∴ 5y + 6y = 220
⇒ 11y = 220
⇒ y =
⇒ y = 20°
∴ ∠B = 5y = 5 × 20 = 100°
and
∴ ∠D = 6y = 6 × 20 = 120°
Thus, the measure of angles are:
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Answer:
In a quadrilateral ABCD,
∠A +∠C = 140,
∠A : ∠C = 1 : 3
and
∠B : ∠D = 5 : 6
To find:
The angles A, B, C & D
Solution:
∵ Since ∠A : ∠C = 1 : 3, so let's assume,
"x" → represents the measure of the ∠A
"3x" → represents the measure of the ∠C
But, ∠A + ∠C = 140° (given)
∴ x + 3x = 140°
⇒ 4x = 140°
⇒ x = \frac{140}{4}
4
140
⇒ x = 35°
∴ ∠A = x = 35°
and
∴ ∠C = 3x = 3 × 35° = 105°
We know, in quadrilateral ABCD, we have
∠A + ∠B + ∠C + ∠D = 360° ..... [angle sum property of a quadrilateral]
⇒ ∠B + ∠D + 140° = 360°
⇒ ∠B + ∠D = 360° - 140°
⇒ ∠B + ∠D = 360° - 140°
⇒ ∠B + ∠D = 220°
∵ Since ∠B : ∠D = 5 : 6, so let's assume,
"5y" → represents the measure of the ∠B
"6y" → represents the measure of the ∠D
∴ 5y + 6y = 220
⇒ 11y = 220
⇒ y = \frac{220}{11}
11
220
⇒ y = 20°
∴ ∠B = 5y = 5 × 20 = 100°
and
∴ ∠D = 6y = 6 × 20 = 120°
Thus, the measure of angles are:
\begin{gathered}{\boxed{\bold{\angle A = 35\°}}}\\{\boxed{\bold{\angle B = 100\°}}}\\\\{\boxed{\bold{\angle C = 105\°}}}\\\\{\boxed{\bold{\angle D = 120\°}}}\end{gathered}
∠A=35\°
∠B=100\°
∠C=105\°
∠D=120\°
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