In a quadrilateral abcd angle a + angle b equal to 150 degree and angle c equal to 120 degree find angle dae
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sum of angles of a quadrilateral = 360°
sum of 1rst and 2nd angles = 150°
3rd angle = 120°
4th angle be X
150°+120°+X= 360°
X = 360° - (150°+120°)
= 360° - 270°
= 90°
Therefore, 4th angle is 90°
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sum of 1rst and 2nd angles = 150°
3rd angle = 120°
4th angle be X
150°+120°+X= 360°
X = 360° - (150°+120°)
= 360° - 270°
= 90°
Therefore, 4th angle is 90°
THIS MAY HELP YOU
PLEASE MARK ME AS BRAINLIEST
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