Question

In a quadrilateral ABCD, angle A+ angle C is 2 times angle B + angle D. If angle A = 140° and angle D = 60° then angle B is equal to​

Answer 1

Answer:

140°+c+2(b+60°)= 360°

∠a+∠b+∠c+∠d=360°

b+60+2b+120=360°

3b+180°=360°

3b=180°

b=60°

Step-by-step explanation:

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Answer 2

Answer:

60° is answer dear friend