Question

in a quadrilateral ABCD angle b is equal to 90 degree is equal to angle D prove that twice is a square minus b square is equal to a b square + 8 square + BC square

Answer 1

Since all angles in a rectangle are right angles

So, In ΔABC

AC2 = AB2 + BC2  (Pythagoras Theorem)

⇒ 2AC2 = 2(AB2 + BC2)

⇒ AC2 + AC2 = AB2 + BC2 + AB2+ BC2

⇒ AC2 + BD2 = AB2 + BC2 + CD2+ AD2  (opposite sides of a rectangle are equal and diagonals of a rectangle are equal)
2AC2  = AB2 + BC2 + CD2+ AD2
​Regards

Answer 2

Answer:

(AB+AC)(AC-AB)=(CD+BD)(CD-BD)

Step-by-step explanation:

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